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6t^2-36t+54=0
a = 6; b = -36; c = +54;
Δ = b2-4ac
Δ = -362-4·6·54
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$t=\frac{-b}{2a}=\frac{36}{12}=3$
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